How do I create a mechanic exactly like sonic when he loses his rings?

Hey guys, I'm trying to recreate a sonic game, but I'm stuck on the part that I get hit and drop all my rings. I made the ring dropping, bouncing and everything, my problem is to drop the exact amount of rings that I had before I got hit, like a for or repeat loop. How can I do it?

I thought they all spawned at the same time on sonic games? So if rings a global variable, you just create that number of rings. If you are doing it one at a time I guess you can create a ring as you subtract 1 from rings variable until rings variable is 0.

Doing it one at a time would not look like they dropped all at the same time, they would begin to drop every tick. How would I compare the variable and spawn a certain number of them at once? Like "Spawn X (number of rings) objects"?

The only way I can think of if like "if 40 rings" followed by 40 spawn action lines, and doing that for 39, 38 and all number of rings possible, which I don't think it's fine.

That would also spawn of per tick. Every tick it would spawn one until the repeat count is reached. Really stuck on this one, seems complex.

Should be easy peasy with a While loop! When Sonic gets hit, do this:

WHILE "ringsVariable" > 0 ------------- Spawn 1 Ring, Subtract 1 from "ringsVariable"

This will all take place in 1 tick and so the player will see 40 rings appear and the ring counter change to 0.

That worked! Thanks a lot

No, your solution will add 1 ring every tick, which is what OP doesn't want. Making it a While loop will make all 40 rings appear in 1 tick. Otherwise, if the user has 90 rings it might take 1.5 seconds to drop them all at 60fps!

The event using the repeat condition is obviously not to be used as a top event that would indeed happened every tick, but to be used as a sub-event to the event that handles the collision with the main character.

When asking for help, do always provide a capx of your project to prevent this kind of misunderstanding.

The solution to the asked question has already been given in three different implementation ways nonetheless.