Event condition- there is NOT a box at X,Y

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• So i need a condition which will determine if there is not a box at X,Y.

To determine if there is one, i used

for each box

box.x=x

box.y=y

but if you do an else, it will check the first box to see if it is at x,y, then if the first box is not there it will go to the else. I want it to check ALL the instances, and if none of them are at x,y, then it determines there is no box at x,y.

make sense?

• right click any condition, invert condition.

• yes, but what do I invert?

obviously not "for each box".

If i invert the box.x=x, then im just checking if theres a box at y and not at x.

if i invert the box.y=y, then im jest checking if theres a box at x and not y.

if i invert both box.x=x and box.y=y, then im checking if theres a box somewhere else.

but theres fifteen boxes in the game- of course theres one somewhere else. i want to know if there is NOT one there.

• private variable ('anybox')=0

for each box

----if box at x

--------if box at y -----anybox =1

if anybox = 1, that means there is at least one box there

else, no boxes are there

• But what if the box moves? The variable still equals 1, but theres no box there.

• perhaps a bit more information would help. i am making a game where the player picks up and moves boxes. Currently you can pick up the bottom box in a stack. That should not be. You should only be able to pick up the top box. So, i used the condition described at the begining to find out if a box was under another box. If so, it gets stuck. THe problem is, once the player moves the box above, the box below still thinks it's stuck.

• if you set it to 0 before you do the for each condition each time it will be 0 if its not there, and 1 if it is,

regardless of what the condition was in the last tick

also, for what you described, the "is overlapping at offset" condition might be more appropriate

and would be much simpler, though you'll have to use the family trick

for instance

box is overlapping "boxfamily" at offset x=0,y=-5

make box immovable

you have to do this with a family,

as in : Box is overlapping Box

it will think you want both boxes to be immovable

so by separating the condition with a family, it understands the boxes you are overlapping

are not meant to be picked for the actions

example:

drag and drop boxes

http://dl.getdropbox.com/u/1013446/boxthing.cap

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• THANK YOU! Overlap at offset makes EVERYTHING in my life better. It made doing this a 30 second affair, not the 5 hour one it was, and it will make the other things that i need to fix eaiser.

You are a lifesaver.