How do I remove and item from a 2d array and have all proceeding values shift up.

I have a 2d array of data. A grid x and y which is 16 by 16. Each element contains some data ( a string).

I want to remove a single value from the grid and everything after if shift up so there are no spaces. Imagine removing an entry from a list of items, you want everything to shift up and not display empty spaces.

Because this is a 2d grid I would want everything on the same row to the right to shift left and the same for all rows below it with values moving up a row to fill spaces at the right hand side of each row.

I have been trying to figure this out for hours with my 2d grid array but cant seem to do it. Is there no command for the array which splices them like this automatically?

The delete seems to delete an entire axis which is not what I want. Just a single element needs to be removed.

Note: I want the array size to stay the same (16 by 16) all the time. but ones with null/zero values be put at the end.

Yes that's exactly what I mean. Apologies for the confusion.

Overnight I had the idea that a good approach to this might be to create a temporary 16 by 16 array and then for each element in the original array; copy values across IF they are not null/zero. The new array would then be arranged as in the above example. ie no gaps in the middle.

Testing now...

UPDATE. Not possible because it seems there is no simple way to just push something to the end of a 2d array. ?!?

It looks like another approach maybe to convert everything down to a 1d array, do the edits and then turn it back into a 2d array.

Another idea is to have 16 1 dimensional arrays of 16 elements each...

...although I suspect this is waaay overcomplicated for what it needs to be.

Accepting all ideas here :)

You can use a single 1D array and just think of it as a 2D array :)

Make an array with width=256 and use it to store 16x16 values. If you need an entry, say, for (X=5,Y=1), it's Array.At(1*16+5)

Or Array.At(Y*16+X)

Then you can easily remove entries in the middle and shift the rest of the array using "pop" action.

You should be able to treat the 2d array as a 1d one. If 0 means empty do:

on function “shiftArray”
Repeat 16*16-1 times
Array: at (loopindex%16, int(loopindex/16)) =0
— array: set at (loopindex%16, int(loopindex/16)) to Array.at((loopindex+1)%16, int((loopindex+1)/16))
— array: set at ((loopindex+1)%16, int((loopindex+1)/16)) to 0