[Solved] Calculate exact frames/sec for a set distance

timeTaken = abs((sqrt(2 * y_1 * g - 2 * y_0 * g + (sin(theta) * speed)^2) - sin(theta) * speed) / g)[/code:4pq98oc2]
Where:
[ul]
	[li]y_0 is the starting y coordinate of the projectile[/li]
	[li]y_1 is the y coordinate of the projectile's target[/li]
	[li]g is the acceleration of gravity in pixels per second[/li]
	[li]theta is the angle between the ground and the initial direction of the projectile[/li]
	[li]speed is the initial speed of the projectile[/li]
[/ul]
The following equation should get you the required animation speed of the projectile.

[code:4pq98oc2]animationSpeed = numberOfFrames / timeTaken[/code:4pq98oc2]
This will work for a side view where the projectile start and end positions lie at separate Y coordinates.  If you're talking about a top down view, the following(much simpler) equation should get you what you need.

[code:4pq98oc2]animationSpeed = numberOfFrames / (distance(projectileStartX, projectileStartY, projectileEndX, projectileEndY) / projectileSpeed)[/code:4pq98oc2]

timeTaken = abs( (sqrt(2 * distance(attackerX, attackerY, Token.X, Token.Y) * acceleration + initialSpeed^2) - initialSpeed) / acceleration )[/code:3hyecwtn]
[code:3hyecwtn]animationSpeed = numberOfFrames / timeTaken[/code:3hyecwtn]
Your code looks fine as far as implementing the equation I gave you.  You should check your animation and make sure each frame has a speed of 1, as higher or lower values could throw things off.  It could additionally be an issue of timing differences.  I've given you mathematically exact equations, but simulations like these aren't necessarily mathematically ideal.