[Solved] How do I add a random value to a specific variable

Hello !

I am trying to add a random value to a variable. Let me explain more clearly.

I have a variable " Value " on a sprite, which has to get a random value at the loading of the layout.

There is where am i at the moment :

So, it choose an ID between 1 and 8 (there is 8 occurrence). Then it applies to this specific one, one of the value in the choose. From there everything is working.

My problem is, I need 2 things :

• A loop (but never used it, so i don't know which one and how to configure it) so I can apply it to every occurrences.
• Something to put no duplication into it because each value (top ...) as to be attribuate only ONCE (and this is very important).

After that, I have to do this with an other loop to apply to 8 new occurence (black and white ones) and this one has to have some values multiple times and i'm lost aswell.

Any helps is welcome!

Regards.

Well i found the loop, I'll just use the for each instance, which works perflectly and it's easy.

But I still have the problem about the choose, if only a "choose once" could exist haha

It's not really what I'm looking for.

I have a list with height directions that I need to attribute to the variable "Value" for each pieces of my sprite, but the problem is I need to attriburte the direction only 1 time

It is exactly what you look for. (if i understand what you want)

Populate the array with the 8 directions. Give the sprites an instance variable 'direction' (text)

I suppose you have 8 Sprites.

For each 'sprite'

................... sprite > set instance variable 'direction' to BHTSmartRandom.Next

They all have now a random chosen non repetitive direction. No idea why you need to distribute with a value.

Oh yeah, way easier with the way you explain it.

Just a question about this, I want to access to the string, not the number. But when I look in the debugger I see a number, not the real value (like "top").

Just like the screens shows :

Set Direction to directions.At(BHTSmartRandom.Next)

Oh ! Thank you, works perfectly <3