Oh, trigonometry~

I never figured out trigonometry enough to solve this little problem I have.

As you may know, when a layer rotates in construct, it rotates with its axis included, so the coordinates move with it, something like this:

<img src="http://img707.imageshack.us/img707/5083/001sng.png" border="0" />

<img src="http://img26.imageshack.us/img26/8682/002bcp.png" border="0" />

Now, I need a formula that, knowing the angle of rotation of the layer, tells me the visual position of a point (in the example, I would want (0,y) instead of (x,y)).

Any help would be greatly appreciated n__n!

Edit: note that the point can move freely. So I need to know the absolute position of the point of its relative position in the rotated layer.

cx,cy are the coordinates of the center of rotation

xR,yR are the coordinates in a rotated layer at angle layerangle

x,y are the coordinates in an unrotated layer

x = cx + cos(-layerangle) * distance(cx,cy,xR,yR)

y = cy + sin(-layerangle) * distance(cx,cy,xR,yR)

It doesn't work because if the layer is not rotated (i.e. layerangle = 0), its sine = 0, so y = cy.

:<

yeah your right

x = cx + cos(-layerangle+angle(cx,cy,xR,yR)) * distance(cx,cy,xR,yR)

y = cy + sin(-layerangle+angle(cx,cy,xR,yR)) * distance(cx,cy,xR,yR)

Thank you very much! It works now!

You'll be in the credits of every game for the contest, it appears xD