Post Data Url returns a 0x0 png

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JustCallum
- Joined 4 Dec, 2013
- 18 topics • 61 posts
1

7 Nov, 2014
Quote

I have a code that gets data(png,jpg and stuff) and save it as a file.

<?php
	// requires php5
	header('Access-Control-Allow-Origin: *');
	define('UPLOAD_DIR', 'static/images/');
	$img = $_POST['img'];
	$img = str_replace('data:image/png;base64,', '', $img);
	$img = str_replace(' ', '+', $img);
	$data = base64_decode($img);
	$file = UPLOAD_DIR . uniqid() . '.png';
	$success = file_put_contents($file, $data);
	print $success ? $file : 'Unable to save the file.';
?>[/code:1cocpr8o]

The host is DataServer.Airwavestudio.co.uk/<pathhere>  the path here is removed as it can be used to post stuff if gotten hold off.

[img="http://i.gyazo.com/35ad299403b8690b4fd7c39b3414d2a9.png"]
raw:     "type='base64'&image=" & URLEncode(RegexReplace(CanvasSnapshot, "data:image/png;base64,", "", ""))
but everytime it gets posted it makes a 0x0 png file. 
So what am I doing wrong?

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- Joannesalfa
- - Joined 8 May, 2011
  - 319 topics • 3,129 posts
- 1
- 8 Nov, 2014
- Quote
Your Data field doesn't represent valid variable for Post, it just returns nothing, look your php script:

$img = $_POST['img'];

It should be

$img = $_POST['image'];

You don't need to add useless functions because your PHP script already comes same functions as replace function.

Data field, should be:

"image="&CanvasSnapshot

image variable represents post data.

It's simple, that's all.

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https://www.scirra.com/store/royalty-fr ... -image-116