How do I show a random node from a XML

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I'm trying to show a random question from a XML. The variable sporsmalsnr holds a random number. For each node a counter increments. Then I want to loop through all nodes, and show the node where counter = sporsmalsnr. Somehow it doesn't work, as it only shows the first question.

Well, giving it the limitations (round(random(1,2))) will do that, as you're only letting it have one number and that is 1. Try making it (round(random(0,10)))

I have tested it. round(random(1,2)) gives integer 1 or 2. I have two questions in the XML, but only first question is showing.

Even when question number is 2 and counter is 2, it just shows the first question anyway. So it seems that if they are similar, it starts from the first node.

Isn't it zero based? so 1st node is 0...2nd node is 1.. Try using round(random(0,1)) instead

XPath use 1-based index, so to get the first question, use this :

/questions/question[1]/@text"[/code:1z9wnwkk]
For the 2nd :
[code:1z9wnwkk]/questions/question[2]/@text"[/code:1z9wnwkk]
And so on so forth.

In your case you could just ditch the for each node and directly use the action set text to :
[code:1z9wnwkk]XML.StringValue("/questions/question[" & sporsmal & "]/@text")[/code:1z9wnwkk]